1912 United States presidential election in Maryland

1912 United States presidential election in Maryland

← 1908 November 5, 1912 1916 →
 
Nominee Woodrow Wilson Theodore Roosevelt William Howard Taft
Party Democratic Progressive Republican
Home state New Jersey New York Ohio
Running mate Thomas R. Marshall Hiram Johnson Nicholas M. Butler
Electoral vote 8 0 0
Popular vote 112,674 57,789 54,956
Percentage 48.57% 24.91% 23.69%

County Results

President before election

William Howard Taft
Republican

Elected President

Woodrow Wilson
Democratic

The 1912 United States presidential election in Maryland took place on November 5, 1912, as part of the 1912 United States presidential election. State voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

Maryland was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 48.57% of the popular vote, against the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 24.91% of the popular vote and the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 23.69% of the popular vote.[1] As of the 2020 presidential election, this is the first and only time that Garrett County did not support the Republican candidate.[2] As of 2020, this is also the last time the Democratic candidate won Carroll County by more than 10%.[3]

This was the first time since 1892 that a Democrat won the popular vote in Maryland.

  1. ^ "1912 Presidential Election Results Maryland".
  2. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
  3. ^ "Maryland". Google Docs. Retrieved August 28, 2022.