1928 United States presidential election in West Virginia

1928 United States presidential election in West Virginia

← 1924 November 6, 1928 1932 →
 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 8 0
Popular vote 375,551 263,784
Percentage 58.43% 41.04%

County Results

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

The 1928 United States presidential election in West Virginia took place on November 6, 1928, as part of the 1928 United States presidential election which was held throughout all contemporary 48 states. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

West Virginia voted for the Republican nominee, former Secretary of Commerce Herbert Hoover of California, over the Democratic nominee, Governor Alfred E. Smith of New York. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith ran with Senator Joseph Taylor Robinson of Arkansas.

Hoover won the state by a margin of 17.39 percent, with his margin undoubtedly enhanced by Appalachian anti-Catholicism against New Yorker Smith.[1] This was the last time that a non-incumbent Republican won West Virginia until 2000. Hoover was the only Republican to carry Logan County until John McCain in 2008, the first-ever Republican victor in Wetzel County, the first Republican since Ulysses S. Grant in 1868 to carry Greenbrier County, and the first Republican since Abraham Lincoln in 1864 to carry Wayne County.[2]

  1. ^ Menendez, Albert J. (2005). The Geography of Presidential Elections in the United States, 1868-2004. McFarland. pp. 58–59. ISBN 0786422173.
  2. ^ Menendez. The Geography of Presidential Elections in the United States, pp. 334-336