1940 United States presidential election in Indiana

1940 United States presidential election in Indiana

← 1936 November 5, 1940[1] 1944 →

All 14 Indiana votes to the Electoral College
 
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state New York New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 14 0
Popular vote 899,466 874,063
Percentage 50.45% 49.03%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Indiana took place on November 5, 1940, as part of the 1940 United States presidential election. State voters chose 14[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Indiana was won by Wendell Willkie (RNew York), running with Senate Minority Leader Charles L. McNary of Oregon, with 50.45% of the popular vote, against incumbent President Franklin D. Roosevelt (DNew York), running with Secretary of Agriculture Henry A. Wallace, with 49.03% of the popular vote.[3][4]

  1. ^ "United States Presidential election of 1940 – Encyclopædia Britannica". Retrieved August 18, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 18, 2018.
  3. ^ "1940 Presidential General Election Results – Indiana". Retrieved August 18, 2018.
  4. ^ "The American Presidency Project – Election of 1940". Retrieved August 18, 2018.