1940 United States presidential election in Oklahoma

1940 United States presidential election in Oklahoma

← 1936 November 5, 1940[1] 1944 →

All 11 Oklahoma votes to the Electoral College
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 11 0
Popular vote 474,313 348,872
Percentage 57.41% 42.23%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Oklahoma took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose 11[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Oklahoma was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 57.41% of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 42.23% of the popular vote.[3][4]

  1. ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved September 11, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved September 11, 2018.
  3. ^ "1940 Presidential General Election Results - Oklahoma". Retrieved September 11, 2018.
  4. ^ "The American Presidency Project - Election of 1940". Retrieved September 11, 2018.