1940 United States presidential election in Washington (state)

1940 United States presidential election in Washington (state)

← 1936 November 5, 1940[1] 1944 →

All 8 Washington votes to the Electoral College
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 8 0
Popular vote 462,145 322,123
Percentage 58.22% 40.58%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Washington took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Washington was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 58.22% of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 40.58% of the popular vote.[3][4]

  1. ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved December 19, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved December 19, 2018.
  3. ^ "1940 Presidential General Election Results - Washington". Retrieved December 19, 2018.
  4. ^ "The American Presidency Project - Election of 1940". Retrieved December 19, 2018.