1944 United States presidential election in Rhode Island

1944 United States presidential election in Rhode Island

← 1940 November 7, 1944 1948 →
 
Nominee Franklin D. Roosevelt Thomas E. Dewey
Party Democratic Republican
Home state New York New York
Running mate Harry S. Truman John W. Bricker
Electoral vote 4 0
Popular vote 175,356 123,487
Percentage 58.59% 41.26%


President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1944 United States presidential election in Rhode Island took place on November 7, 1944, as part of the 1944 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

Rhode Island voted Democratic candidate, incumbent President Franklin D. Roosevelt of New York, over the Republican candidate, Governor Thomas E. Dewey of New York. Roosevelt ran with Senator Harry S. Truman of Missouri as his running mate, while Dewey ran with Governor John W. Bricker of Ohio as his running mate.

Roosevelt won the state by a margin of 17.33%. Rhode Island was one of six states that became more Democratic compared to 1940, alongside Michigan, Minnesota, New York, North Dakota, and Illinois.