1948 United States presidential election in Nevada

1948 United States presidential election in Nevada

← 1944 November 2, 1948[1] 1952 →

All 3 Nevada votes to the Electoral College
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 3 0
Popular vote 31,291 29,357
Percentage 50.37% 47.26%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in Nevada took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Nevada was won by incumbent President Harry S. Truman (DMissouri), running with Senator Alben W. Barkley, with 50.37% of the popular vote, against Governor Thomas E. Dewey (RNew York), running with Governor Earl Warren, with 47.26% of the popular vote.[3][4] This was the last election where voters in Nevada selected presidential electors directly.

  1. ^ "United States Presidential election of 1948 – Encyclopædia Britannica". Retrieved October 26, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 26, 2017.
  3. ^ "1948 Presidential General Election Results – Nevada". Retrieved October 26, 2017.
  4. ^ "The American Presidency Project – Election of 1948". Retrieved October 26, 2017.