1948 United States presidential election in Rhode Island

1948 United States presidential election in Rhode Island

← 1944 November 2, 1948 1952 →

Nominee Harry S. Truman Thomas E. Dewey Party Democratic Republican Home state Missouri New York Running mate Alben William Barkley Earl Warren Electoral vote 4 0 Popular vote 188,736 135,787 Percentage 57.59% 41.44%

County Results Municipality Results Truman   50-60%   60-70%   70-80% Dewey   50-60%   60-70%   70-80%

President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

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v t e

The 1948 United States presidential election in Rhode Island took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

Rhode Island was won by Democratic candidate, incumbent President Harry S. Truman of Missouri, over the Republican candidate, Governor Thomas E. Dewey of New York. Truman ran with Senator Alben W. Barkley of Kentucky as his running mate, while Dewey ran with Governor Earl Warren of California as his running mate.

Truman won Rhode Island by a margin of 16.15%.