1948 United States presidential election in West Virginia

1948 United States presidential election in West Virginia

← 1944 November 2, 1948[1] 1952 →

All 8 West Virginia votes to the Electoral College
 
Nominee Harry S. Truman Thomas E. Dewey
Party Democratic Republican
Home state Missouri New York
Running mate Alben W. Barkley Earl Warren
Electoral vote 8 0
Popular vote 429,188 316,251
Percentage 57.32% 42.24%

County Results

President before election

Harry S. Truman
Democratic

Elected President

Harry S. Truman
Democratic

The 1948 United States presidential election in West Virginia took place on November 2, 1948, as part of the 1948 United States presidential election. West Virginia voters chose eight[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

West Virginia was won by incumbent President Harry S. Truman (DMissouri), running with Kentucky Senator Alben W. Barkley, with 57.32 percent of the popular vote, against Governor Thomas E. Dewey (RNew York), running with Governor Earl Warren, with 42.24 percent of the popular vote.[3][4]

The Progressive Party submitted 10,189 signatures, greater than the 7,155 required, and enough were validated to appear on the ballot. Their candidate in the concurrent gubernatorial election was removed from the ballot by a court ruling.[5]

  1. ^ "United States Presidential election of 1948 — Encyclopædia Britannica". Retrieved December 19, 2017.
  2. ^ "1948 Election for the Forty-First Term (1949–53)". Retrieved December 19, 2017.
  3. ^ "1948 Presidential General Election Results — West Virginia". Retrieved December 19, 2017.
  4. ^ "The American Presidency Project — Election of 1948". Retrieved December 19, 2017.
  5. ^ Schmidt 1960, p. 137.