1950 Iowa Senate election

1950 Iowa Senate election

← 1948 November 7, 1950 1952 →

22 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 43 7
Seats after 41 9
Seat change Decrease2 Increase2

The 1950 Iowa State Senate elections took place as part of the biennial 1950 United States elections. Iowa voters elected state senators in 22 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1950 elections is provided by the Iowa General Assembly here.

The primary election on June 5, 1950, determined which candidates appeared on the November 7, 1950 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa state Senate with 43 seats to Democrats' 7 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 19 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1950 general election with the balance of power shifting to Republicans holding 41 seats and Democrats having 9 seats (a net gain of 2 seats for Democrats).

  1. ^ "Primary Election 1950 For State Senator" (PDF). Iowa Official Register. Retrieved June 15, 2020.
  2. ^ "General Election 1950 For State Senator" (PDF). Iowa Official Register. Retrieved June 15, 2020.