1976 United States presidential election in Rhode Island

1976 United States presidential election in Rhode Island

← 1972 November 2, 1976 1980 →
Turnout76.4%[1]
 
Nominee Jimmy Carter Gerald Ford
Party Democratic Republican
Home state Georgia Michigan
Running mate Walter Mondale Bob Dole
Electoral vote 4 0
Popular vote 227,636 181,249
Percentage 55.36% 44.08%


President before election

Gerald Ford
Republican

Elected President

Jimmy Carter
Democratic

The 1976 United States presidential election in Rhode Island took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

Rhode Island was won by Jimmy Carter (DGeorgia), with 55.36% of the popular vote. Carter defeated incumbent President Gerald Ford (RMichigan), who finished with 44.08% of the popular vote. No third-party candidate received any votes.

Jimmy Carter went on to become the 39th president of the United States.[2]

  1. ^ This figure is calculated by dividing the total number of votes cast in 1976 (416,583) by an estimate of the number of registered voters in Rhode Island in 1976 (544,992). See "General Election November 2, 1976". Rhode Island Board of Elections. Retrieved February 6, 2018.
  2. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved February 11, 2024.