1988 United States presidential election in Tennessee

1988 United States presidential election in Tennessee

← 1984 November 8, 1988 1992 →
 
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 11 0
Popular vote 947,233 679,794
Percentage 57.89% 41.55%


President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

The 1988 United States presidential election in Tennessee took place on November 8, 1988. All 50 states and the District of Columbia were part of the 1988 United States presidential election. Tennessee voters chose 11 electors to the Electoral College, which selected the president and vice president. Tennessee was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Tennessee weighed in for this election as eight points more Republican than the national average. Tennessee was the only state to vote more Republican than in 1984. As of the 2020 presidential election, this was the last time the Republican candidate carried Davidson County (home of Nashville) and Shelby County (home of Memphis), both of which have become staunch, and the only, Democratic strongholds into the 21st century.[1] Hardeman County, Tennessee would not vote for a Republican again until 2016 United States presidential election

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