1990 Calder Cup playoffs

1990 Calder Cup playoffs
Tournament details
DatesApril 4 – May 18, 1990
Teams8
Final positions
ChampionsSpringfield Indians
Runner-upRochester Americans
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The 1990 Calder Cup playoffs of the American Hockey League began on April 4, 1990.[1] The eight teams that qualified, four from each division, played best-of-seven series for Division Semifinals and Division Finals. The division champions played a best-of-seven series for the Calder Cup. The Calder Cup Final ended on May 18, 1990, with the Springfield Indians defeating the Rochester Americans four games to two to win the Calder Cup for the sixth time in team history.[2] Despite an injury preventing him from playing in the final game, Springfield goaltender Jeff Hackett won the Jack A. Butterfield Trophy as the MVP of the playoffs.[3]

The league instituted trophies for division champions in the playoffs; the Richard F. Canning Trophy in the North Division, and the Robert W. Clarke Trophy in the South Division.[4][5]

  1. ^ 1990 AHL playoff results The Internet Hockey Database. Retrieved on May 5, 2008.
  2. ^ Calder Cup champions Archived 2008-05-26 at the Wayback Machine caldercup.com. Retrieved on May 5, 2008.
  3. ^ Jack A. Butterfield Trophy Archived 2008-09-17 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.
  4. ^ Richard F. Canning Trophy Archived 2008-01-20 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.
  5. ^ Robert W. Clarke Trophy Archived 2008-01-20 at the Wayback Machine ahlhalloffame.com. Retrieved on May 6, 2008.