1992 United States presidential election in Alaska

1992 United States presidential election in Alaska

← 1988 November 3, 1992 1996 →
 
Nominee George H. W. Bush Bill Clinton Ross Perot
Party Republican Democratic Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 3 0 0
Popular vote 102,000 78,294 73,481
Percentage 39.46% 30.29% 28.43%


President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

The 1992 United States presidential election in Alaska took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Alaska was won by incumbent President George H. W. Bush (R-Texas) with 39.4% of the popular vote over Governor Bill Clinton (D-Arkansas) with 30.2%. Bush won Alaska by a margin of 9.2%. Businessman Ross Perot (I-Texas) finished in third, with 28.4% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush. Alaska has only voted Democratic once, and that was in 1964 for Lyndon B. Johnson.[2] As of 2020, this is the last time the Republican margin of victory in Alaska has been in single digits and the last time that the state was won with a plurality.

With 28.43% of the popular vote, Alaska would prove to be Perot's second strongest state after Maine. Alaska was also one of seven states to give a county to Perot, the others being California, Colorado, Kansas, Maine, Nevada and Texas. Alaska awarded Perot Denali Borough, making it the last time it did not vote for the Republican candidate.[3]

  1. ^ Cite error: The named reference results was invoked but never defined (see the help page).
  2. ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 8, 2012.
  3. ^ "1992 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.