1992 United States presidential election in Missouri|
|
|
|
 County Results
|
Clinton
30–40%
40–50%
50–60%
60–70%
|
Bush
30–40%
40–50%
50–60%
| |
|
The 1992 United States presidential election in Missouri was held on November 3, 1992, as part of the broader 1992 United States presidential election in all fifty states and the District of Columbia. Voters chose 11 electors, or representatives to the Electoral College, who voted for President and Vice-president.
From 1904 to 2004, Missouri voted for the eventual winner of every presidential election except 1956. The state was won in 1992 by Governor of Arkansas Bill Clinton (D) with 44.07 percent of the popular vote, over incumbent President George Herbert Walker Bush (R) with 33.92 percent of the popular vote — the smallest vote share for a Republican since 1860 when the party was not seriously contesting slave states outside of the Missouri Rhineland.[1] Independent Ross Perot performed extremely well for a third-party candidate with 21.69 percent of the popular vote — the best third-party performance in Missouri since Constitutional Unionist John Bell in that same 1860 election.[1]
.jpg)
