1992 United States presidential election in Nebraska

1992 United States presidential election in Nebraska

← 1988 November 3, 1992 1996 →

Nominee George H. W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 5 0 0 Popular vote 344,346 217,344 174,687 Percentage 46.58% 29.40% 23.63%

County Results Bush   30–40%   40–50%   50–60%   60–70% Clinton   40–50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

Elections in Nebraska
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The 1992 United States presidential election in Nebraska took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Nebraska was won by incumbent President George H. W. Bush (R-Texas) in a landslide, with 46.58% of the popular vote over Governor Bill Clinton (D-Arkansas) with 29.40%. Businessman Ross Perot (I-Texas) finished in third, with 23.63% of the popular vote.^[1] Clinton ultimately won the national election, defeating Bush and Perot in by a large margin in the popular vote and electoral college.^[2]