1992 United States presidential election in North Dakota

1992 United States presidential election in North Dakota

← 1988 November 3, 1992 1996 →
 
Nominee George H. W. Bush Bill Clinton Ross Perot
Party Republican Democratic–NPL Independent
Home state Texas Arkansas Texas
Running mate Dan Quayle Al Gore James Stockdale
Electoral vote 3 0 0
Popular vote 136,244 99,168 71,084
Percentage 44.22% 32.18% 23.07%

County Results

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic–NPL

The 1992 United States presidential election in North Dakota took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

North Dakota was won by incumbent President George H. W. Bush (R-Texas) with 44.22% of the popular vote over Governor Bill Clinton (D-Arkansas) with 32.18%. Businessman Ross Perot (I-Texas) finished in third, with 23.07% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.[2]

  1. ^ Cite error: The named reference results was invoked but never defined (see the help page).
  2. ^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 9, 2012.