1992 United States presidential election in Tennessee

1992 United States presidential election in Tennessee
Clinton 40–50% 50–60% 60–70% 70–80%	Bush 40–50% 50–60%
President before election; George H. W. Bush; Republican	Elected President ; Bill Clinton; Democratic

The 1992 United States presidential election in Tennessee took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Tennessee was won by Governor Bill Clinton (D-Arkansas) with 47.08% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 42.43%. Businessman Ross Perot (I-Texas) finished in third, with 10.09% of the popular vote.^[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.^[2]

Clinton, from neighboring Arkansas, benefited from having the state's junior U.S. Senator Al Gore as his vice presidential running mate. As of the 2020 presidential election^[update], this is the last election in which Rutherford County, Sumner County, Wilson County, Lincoln County, Claiborne County, Hardin County, Macon County, Bledsoe County, and Pickett County voted for a Democratic presidential candidate.^[3]

^ Cite error: The named reference results was invoked but never defined (see the help page).
^ "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 9, 2012.
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[results-1] Cite error: The named reference results was invoked but never defined (see the help page).

[2] "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 9, 2012.

[How-3] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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