 1999 CONCACAF Champions' Cup logo | |
| Tournament details | |
|---|---|
| Host country | United States |
| City | Whitney, Nevada |
| Dates | September 28 – October 3 |
| Teams | 8 (from 5 associations) |
| Venue(s) | Sam Boyd Stadium |
| Final positions | |
| Champions |  Necaxa (1st title) |
| Runners-up |  Alajuelense |
| Tournament statistics | |
| Matches played | 8 |
| Goals scored | 18 (2.25 per match) |
← 1998 2000 → | |
The 1999 CONCACAF Champions' Cup was the 35th edition of the annual international club football competition held in the CONCACAF region (North America, Central America and the Caribbean), the CONCACAF Champions' Cup. It determined that year's club champion of association football in the CONCACAF region.
The Final Tournament was held at Sam Boyd Stadium in Whitney, Nevada in the United States.[1] Necaxa defeated Alajuelense in the final by a score of 2-1.[2]
- ^ "Defending champion D.C., Chicago will compete". ESPN. AP. September 28, 1999. Retrieved 2019-02-23.
- ^ http://www.concacaf.com/viewCompetition.aspx?id=230[permanent dead link]