 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
 County results
Bush 50-60% 60-70% 70-80% 80-90%
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in Wyoming |
|---|
 |
The 2000 United States presidential election in Wyoming took place on November 7, 2000, and was part of the 2000 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Wyoming was won by incumbent Texas Governor George W. Bush by a massive 40.06% margin of victory, and his 67.76% of the popular vote made the state his strongest victory in the 2000 election.[1] He was accompanied on the Republican ticket by vice presidential nominee Dick Cheney, formerly a member of the U.S. House of Representatives from Wyoming's at-large district. As of the 2020 presidential election[update], this is the last time a Republican won Teton County, and thus is also the last time a nominee of any party carried every county in the state, even though subsequent Republican nominees such as Donald Trump have exceeded Bush's share of the overall vote in Wyoming.
- ^ "2000 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.