2006 Iowa gubernatorial election

2006 Iowa gubernatorial election

← 2002 November 7, 2006 2010 →
 
Nominee Chet Culver Jim Nussle
Party Democratic Republican
Running mate Patty Judge Bob Vander Plaats
Popular vote 569,021 467,425
Percentage 54.0% 44.4%

County results
Culver:      40–50%      50–60%      60–70%
Nussle:      40–50%      50–60%      60–70%      70–80%      80–90%

Governor before election

Tom Vilsack
Democratic

Elected Governor

Chet Culver
Democratic

The 2006 Iowa gubernatorial election took place November 7, 2006. The incumbent governor, Tom Vilsack, a Democrat, had served two terms and decided not to seek a third term. In the election, Chet Culver defeated Jim Nussle to win the governorship, by a margin of 54% to 44%.[1]

As of 2022, this was the last time a Democrat won the governorship of Iowa. This election marks the first time Democrats won three consecutive gubernatorial elections in the state since 1966, and the only time Democrats have ever done so for four-year terms.

  1. ^ Beaumont, Thomas (November 8, 2006). "Culver sails into victory". Des Moines Register. Retrieved November 9, 2006.