2018 United States Senate election in Wyoming

2018 United States Senate election in Wyoming

← 2012 November 6, 2018 2024 →
Turnout77.43% Increase
 
Nominee John Barrasso Gary Trauner
Party Republican Democratic
Popular vote 136,210 61,227
Percentage 66.96% 30.10%

Barrasso:      40–50%      50–60%      60–70%      70–80%      80–90%      >90%
Trauner:      40–50%      50–60%      60–70%      70–80%
     No votes

U.S. senator before election

John Barrasso
Republican

Elected U.S. Senator

John Barrasso
Republican

The 2018 United States Senate election in Wyoming took place on November 6, 2018, to elect a member of the United States Senate to represent the State of Wyoming. The primary election took place August 21, 2018.[1] Republican John Barrasso won re-election with 67% percent of the vote, the lowest percentage of his three U.S. Senate campaigns and the closest a Democrat has come to winning a seat since the 1996 election, and the first time since that election in which Democrats managed to even win counties in the state, those being Teton and Albany, and the first time that the Democratic candidate won any counties for this seat since 1994. Trauner was the first Democrat to win Teton county in a Senate contest since 1940, and the first ever losing Democrat to do so.

  1. ^ "2018 Key Election Dates" (PDF). Wyoming Secretary of State.