2019 FIFA Beach Soccer World Cup OFC qualifier | |
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Tournament details | |
Host country | Tahiti |
City | Papeete |
Dates | 17–22 June |
Teams | 5 (from 1 confederation) |
Venue(s) | 1 (in 1 host city) |
Final positions | |
Champions | Tahiti (2nd title) |
Runners-up | Solomon Islands |
Third place | New Caledonia |
Fourth place | Vanuatu |
Tournament statistics | |
Matches played | 12 |
Goals scored | 149 (12.42 per match) |
Attendance | 8,400 (700 per match) |
Top scorer(s) | Patrick Tepa (12 goals) |
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The 2019 OFC Beach Soccer Nations Cup was the sixth edition of the OFC Beach Soccer Nations Cup (previously called the OFC Beach Soccer Championship), the premier beach soccer tournament contested by Oceanian men's national teams, organised by the Oceania Football Confederation (OFC). The competition returns after a six-year absence.
The tournament took place in Aorai Tini Hau, Papeete, Tahiti from 17 to 22 June 2019.[1] It was originally scheduled to take place from 15 to 22 September 2018 in Pā'ōfa'i Gardens.[2][3] However, in August 2018, it was announced that the tournament had been postponed until June 2019 in order to allow more teams to participate.[4][5]
The tournament also acted as the qualification tournament for Oceanian teams to the 2019 FIFA Beach Soccer World Cup in Paraguay; the winners qualified.[6]
The Solomon Islands were the defending champions, but lost in the final and so did not qualify.