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Holcomb: 30–40% 40–50% 50–60% 60–70% 70–80% 80–90% >90% Myers: 40–50% 50–60% 60–70% 70–80% 80–90% >90% Tie: 40–50% 50% No data | |||||||||||||||||||||||||
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Elections in Indiana |
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The 2020 Indiana gubernatorial election was won by incumbent Republican Eric Holcomb on November 3, 2020. The election was held concurrently with the 2020 U.S. presidential election, as well as elections to the United States House of Representatives and various state and local elections.
Holcomb was eligible to run for re-election to a second term in office, and announced his intention to do so on July 13, 2019 alongside his lieutenant governor, Suzanne Crouch.[1] He faced Democrat Woody Myers, the former health commissioner of Indiana (and later, of New York City) and his running mate, Linda Lawson, the former minority leader of the Indiana House of Representatives, in addition to Libertarian Donald Rainwater, a U.S. Navy veteran and his running mate William Henry.[2][3] Primary elections were held on June 2; Holcomb and Myers ran unopposed.
In the general election, Holcomb won re-election to a second term. Myers also became the first major party candidate to receive fewer than one million votes since Republican David McIntosh in 2000.[4] The election was also notable for the strong performance of Libertarian candidate Rainwater, who finished in second place, behind Holcomb and ahead of Myers, in over one-third of Indiana's counties, 33 out of 92.[5] The stronger-than-expected performance by Rainwater was perceived to be a reaction to Governor Holcomb's response to the COVID-19 pandemic, with Rainwater pushing for fewer government restrictions.[6]
The Associated Press’s large-scale pre-election survey found that Eric Holcomb won white Hoosiers 62–27%, while Myers won black Hoosiers 76–20%.[7]
This election marked the worst performance by a Democratic candidate for governor in Indiana history.[8]