Bloomfield | |
|---|---|
 Town hall | |
 Location of the Town of Bloomfield, Wisconsin | |
| Coordinates: 42°32′30″N 88°21′10″W / 42.54167°N 88.35278°W | |
| Country |  United States |
| State |  Wisconsin |
| County | Walworth |
| Area | |
• Total | 33.4 sq mi (86.4 km2) |
| • Land | 32.6 sq mi (84.3 km2) |
| • Water | 0.8 sq mi (2.1 km2) |
| Elevation | 876 ft (267 m) |
| Population (2020) | |
• Total | 1,778 |
| • Density | 170.1/sq mi (65.7/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 262 |
| FIPS code | 55-08275[2] |
| GNIS feature ID | 1582832[1] |
Bloomfield is a town in Walworth County, Wisconsin, United States. The population was 1,778 at the 2020 census. The village of Bloomfield was formed from part of the town on December 20, 2011.[3] The census-designated place of Lake Ivanhoe and unincorporated community of North Bloomfield are located in the town.
- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Boundary Changes". Geographic Changes. Population Division, United States Census Bureau. January 1, 2012. Archived from the original on July 31, 2012. Retrieved February 26, 2013.