Dennehotso, Arizona

Dennehotso, Arizona
Location in Apache County and the state of Arizona
Location in Apache County and the state of Arizona
Dennehotso, Arizona is located in the United States
Dennehotso, Arizona
Dennehotso, Arizona
Location in the United States
Coordinates: 36°50′34″N 109°51′10″W / 36.84278°N 109.85278°W / 36.84278; -109.85278
CountryUnited States
StateArizona
CountyApache
Area
 • Total9.96 sq mi (25.80 km2)
 • Land9.95 sq mi (25.78 km2)
 • Water0.01 sq mi (0.03 km2)
Elevation5,069 ft (1,545 m)
Population
 (2020)
 • Total587
 • Density58.98/sq mi (22.77/km2)
Time zoneUTC-7 (MST)
 • Summer (DST)UTC-6 (MDT)
ZIP code
86535
Area code928
FIPS code04-18580
GNIS feature ID2408658[2]

Dennehotso (Navajo: Deinihootso) is a census-designated place (CDP) in Apache County, Arizona, United States. The population was 746 at the 2010 census.[3]

  1. ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved October 29, 2021.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Dennehotso, Arizona
  3. ^ "Geographic Identifiers: 2010 Demographic Profile Data (G001): Dennehotso CDP, Arizona". U.S. Census Bureau, American Factfinder. Archived from the original on February 12, 2020. Retrieved April 18, 2013.