Dublin, Indiana | |
|---|---|
 | |
 Location of Dublin in Wayne County, Indiana. | |
| Coordinates: 39°48′46″N 85°12′20″W / 39.81278°N 85.20556°W | |
| Country | United States |
| State | Indiana |
| County | Wayne |
| Township | Jackson |
| Area | |
| • Total | 0.53 sq mi (1.37 km2) |
| • Land | 0.52 sq mi (1.34 km2) |
| • Water | 0.01 sq mi (0.04 km2) |
| Elevation | 1,056 ft (322 m) |
| Population (2020) | |
| • Total | 679 |
| • Density | 1,315.89/sq mi (508.23/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-5 (EST) |
| ZIP code | 47335 |
| Area code | 765 |
| FIPS code | 18-18766[3] |
| GNIS feature ID | 2396689[2] |
Dublin is a town in Jackson Township, Wayne County, in the U.S. state of Indiana.[2] The population was 679 at the 2020 census.
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ a b c U.S. Geological Survey Geographic Names Information System: Dublin, Indiana
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.