Farragut, Iowa | |
---|---|
Coordinates: 40°43′12″N 95°28′51″W / 40.72000°N 95.48083°W | |
Country | United States |
State | Iowa |
County | Fremont |
Area | |
• Total | 0.40 sq mi (1.04 km2) |
• Land | 0.40 sq mi (1.04 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 961 ft (293 m) |
Population (2020) | |
• Total | 490 |
• Density | 1,221.95/sq mi (471.76/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 51639 |
Area code | 712 |
FIPS code | 19-26985 |
GNIS feature ID | 2394751[2] |
Farragut is a city in Fremont County, Iowa, United States. The population was 490 at the time of the 2020 census.[3]