First Battle of Oituz

For other battles at the same location, see Second Battle of Oituz and Third Battle of Oituz.
First Battle of Oituz
Part of World War I
Date12–27 October 1916
Location
Border of Austria-Hungary and Romania (today in Bacău and Covasna counties, eastern Romania)
Result Romanian victory
Belligerents
Romania Romania Austria-Hungary Austria-Hungary
German Empire Germany
Commanders and leaders
Romania Eremia Grigorescu
Romania Nicolae Sinescu		 Austria-Hungary Charles I
German Empire Erich von Falkenhayn

The First Battle of Oituz was fought between 12 and 27 October 1916 between the Kingdom of Romania on one side and Austria-Hungary and the German Empire on the other. It was part of the Romanian operations for the defense of the passes in the Carpathians. The objectives of the operation were to resist the enemy attack on the Transylvanian front, to obtain and maintain a defensive device in the Carpathian alignment and to create the conditions for an eventual counter-offensive. At the end, the Central Powers (Germany and Austria-Hungary) failed to defeat the Romanian forces and the battle was a victory for the latter.[1]

The Austro-Hungarian forces were commanded by Charles I of Austria, heir to the Austro-Hungarian throne, while the German army was commanded by General Erich von Falkenhayn.[2] On the other hand, the Romanian commanders were Eremia Grigorescu and Nicolae Sinescu.[1]

  1. ^ a b Romanian Commission of Military History (1989). Istoria militară a poporului român (in Romanian). Vol. 4. Bucharest: Editura Militară.
  2. ^ von Falkenhayn, Erich; Budiș, Alexandru; Franc, C. (1937). Campania Armatei a 9-a împotriva românilor și a rușilor 1916/17 (in Romanian). Verlag nicht ermittelbar. pp. 1–219.