Frankfort, Indiana | |
|---|---|
 Clinton County Courthouse in Frankfort | |
 Flag  Logo | |
 Location of Frankfort in Clinton County, Indiana. | |
| Coordinates: 40°16′47″N 86°30′21″W / 40.27972°N 86.50583°W | |
| Country | United States |
| State | Indiana |
| County | Clinton |
| Township | Center |
| Founded | 1830 |
| Incorporated | 1846 |
| Named for | Frankfurt am Main |
| Government | |
| • Mayor | Judith Sheets (R) |
| Area | |
| • Total | 8.05 sq mi (20.86 km2) |
| • Land | 8.05 sq mi (20.86 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 860 ft (260 m) |
| Population (2020) | |
| • Total | 16,715 |
| • Density | 2,075.11/sq mi (801.21/km2) |
| Time zone | UTC-5 (EST) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 46041 |
| Area code | 765 |
| FIPS code | 18-25324[3] |
| GNIS feature ID | 2394805[2] |
| Website | frankfort-in.gov |
Frankfort is a city in Clinton County, Indiana, United States. It had a population of 16,715 as of the 2020 census. The city is the county seat of Clinton County.[4]
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Frankfort, Indiana
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Find a County". National Association of Counties. Archived from the original on May 31, 2011. Retrieved June 7, 2011.