Town of Freedom, Wisconsin | |
|---|---|
 Location of the Town of Freedom, Sauk County, Wisconsin | |
| Coordinates: 43°26′1″N 89°53′38″W / 43.43361°N 89.89389°W | |
| Country |  United States |
| State |  Wisconsin |
| County | Sauk |
| Area | |
| • Total | 34.7 sq mi (89.9 km2) |
| • Land | 34.6 sq mi (89.6 km2) |
| • Water | 0.1 sq mi (0.3 km2) |
| Elevation | 886 ft (270 m) |
| Population (2000) | |
| • Total | 416 |
| • Density | 12.0/sq mi (4.6/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| Area code | 608 |
| FIPS code | 55-27675[2] |
| GNIS feature ID | 1583243[1] |
| Website | freedomsaukwi.gov |
The Town of Freedom is a located in Sauk County, Wisconsin, United States. The population was 416 at the 2000 census. The unincorporated community of La Rue is located within the town. The town was named from the American ideal of freedom.[3]
- ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ Cole, Harry Ellsworth (1918). A Standard History of Sauk County, Wisconsin. Lewis Publishing Company. p. 410.