Harlan Township, Warren County, Ohio | |
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Coordinates: 39°17′48″N 84°3′56″W / 39.29667°N 84.06556°W | |
Country | United States |
State | Ohio |
County | Warren |
Area | |
• Total | 45.2 sq mi (117.0 km2) |
• Land | 45.2 sq mi (117.0 km2) |
• Water | 0.0 sq mi (0.0 km2) |
Elevation | 899 ft (274 m) |
Population (2020) | |
• Total | 4,929[1] |
• Density | 80.3/sq mi (31.0/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
FIPS code | 39-33474[3] |
GNIS feature ID | 1087115[2] |
Harlan Township is one of the eleven townships of Warren County, Ohio, United States. It is located in the southeast corner of the county. The population was 4,929 as of the 2020 census.