Hayesville, Iowa

Hayesville, Iowa
Location of Hayesville, Iowa
Location of Hayesville, Iowa
Coordinates: 41°15′53″N 92°14′56″W / 41.26472°N 92.24889°W / 41.26472; -92.24889
Country United States
State Iowa
CountyKeokuk
Area
 • Total0.25 sq mi (0.65 km2)
 • Land0.25 sq mi (0.65 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation794 ft (242 m)
Population
 (2020)
 • Total41
 • Density164.00/sq mi (63.31/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
52562
Area code641
FIPS code19-35445
GNIS feature ID2394333[2]

Hayesville is a city in Keokuk County, Iowa, United States. The population was 41 at the time of the 2020 census.[3]

  1. ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Hayesville, Iowa
  3. ^ "2020 Census State Redistricting Data". census.gov. United states Census Bureau. Retrieved August 12, 2021.