  Hoatsin Island Location of Hoatsin Island  Hoatsin Island Hoatsin Island (Antarctic Peninsula) | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°02′22″S 64°09′07″W / 65.03944°S 64.15194°W |
| Archipelago | Wilhelm Archipelago |
| Area | 16.85 ha (41.6 acres) |
| Length | 795 m (2608 ft) |
| Width | 360 m (1180 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Hoatsin Island (Bulgarian: остров Хоацин, romanized: ostrov Hoatsin, IPA: [ˈɔstrof hoɐˈt͡sin]) is the mostly ice-free island 795 m long in southeast–northwest direction and 360 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 16.85 ha.[1]
The feature is so named because of its shape supposedly resembling a hoatzin bird ('hoatsin' in Bulgarian), and in association with other descriptive names of islands in the area.[1]
- ^ a b Hoatsin Island. SCAR Composite Gazetteer of Antarctica