Jackson Township | |
|---|---|
  Jackson Township Location in Arkansas  Jackson Township Jackson Township (the United States) | |
| Coordinates: 36°00′10″N 93°10′50″W / 36.002703°N 93.180608°W[1] | |
| Country | United States |
| State | Arkansas |
| County | Newton |
| Area | |
| • Total | 59.933 sq mi (155.23 km2) |
| • Land | 59.573 sq mi (154.29 km2) |
| • Water | 0.360 sq mi (0.93 km2) |
| Elevation | 994 ft (303 m) |
| Population | |
| • Total | 1,620 |
| • Density | 27/sq mi (10/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code[2][3] | 05-91872 |
| GNIS ID[2][3] | 69678 |
Jackson Township is a township in Newton County, Arkansas, United States.[4] Its total population was 1,620 as of the 2010 United States Census,[1][5] an increase of 1.76 percent from 1,592 at the 2000 census.[6][7]
According to the 2010 Census, Jackson Township is located at 36°00′10″N 93°10′50″W / 36.002703°N 93.180608°W (36.002703, -93.180608).[1] It has a total area of 59.933 square miles (155.23 square kilometers); of which 59.573 sq mi (154.29 km2) is land and 0.360 sq mi (0.93 km2) is water (0.60%).[1] As per the USGS National Elevation Dataset, the elevation is 994 feet (303 m).[2]
The city of Jasper is located within the township.[4]
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