Jackson Township | |
|---|---|
  Jackson Township Location in Arkansas  Jackson Township Jackson Township (the United States) | |
| Coordinates: 33°03′07″N 92°37′33″W / 33.051999°N 92.625904°W[1] | |
| Country | United States |
| State | Arkansas |
| County | Union |
| Area | |
| • Total | 58.338 sq mi (151.09 km2) |
| • Land | 58.116 sq mi (150.52 km2) |
| • Water | 0.222 sq mi (0.57 km2) |
| Elevation | 210 ft (60 m) |
| Population | |
| • Total | 758 |
| • Density | 13/sq mi (5.0/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code[2][3] | 05-91884 |
| GNIS ID[2][3] | 69750 |
Jackson Township is a township in Union County, Arkansas, United States.[4] Its total population was 758 as of the 2010 United States Census,[1][5] a decrease of 1.56 percent from 770 at the 2000 census.[6][7]
According to the 2010 Census, Jackson Township is located at 33°03′07″N 92°37′33″W / 33.051999°N 92.625904°W (33.051999, -92.625904).[1] It has a total area of 58.338 square miles (151.09 square kilometers); of which 58.116 sq mi (150.52 km2) is land and 0.222 sq mi (0.57 km2) is water (0.38%).[1] As per the USGS National Elevation Dataset, the elevation is 210 feet (64 m).[2]
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