Jacksonville Fire and Rescue Department

Jacksonville Fire and Rescue Department
Operational area
CountryUnited States
StateFlorida
CityJacksonville
Agency overview[1]
EstablishedApril 20, 1886 (1886-04-20)
Annual calls151,237 (2018)
Employees1470 (2019)
Annual budget$234 million (2019)
Fire chiefKeith Powers
EMS levelALS
IAFF122
Facilities and equipment[2][3]
Stations70
Engines65
Trucks15
Squads5
Ambulances63
HAZMAT2
USAR12
Airport crash8
Website
Official website
IAFF website

The Jacksonville Fire and Rescue Department (JFRD) provides fire protection and emergency medical services for Jacksonville, Florida, as well as all unincorporated areas of Duval County.

According to a list of the thirty largest fire departments in the United States, based on staff size, JFRD is number eighteen.[4]

Duval County has the fifth largest fire department in the state based on the number of fire stations.[5] JFRD is among the largest departments in the state and the nation. The department is made up of six divisions, sixty-three fire and rescue station locations, a professional career force of roughly thirteen-hundred individuals.[6][7][8]

  1. ^ "Fast Facts". City of Jacksonville. Retrieved 26 February 2015.
  2. ^ "Operations Division". City of Jacksonville. Retrieved 26 February 2015.
  3. ^ "On Scene Newsletter". City of Jacksonville. August 2014. p. 16. Retrieved 26 February 2015.
  4. ^ "Largest Fire Departments in the US". Fire Department. Retrieved 21 June 2014.
  5. ^ "Florida Fire Departments". Fire Departments. Retrieved 21 June 2014.
  6. ^ "JFRD: Our Divisions". COJ.net. Retrieved 21 June 2014.
  7. ^ "JFRD Fast Facts". City of Jacksonville.
  8. ^ Hinson, Don. "Jacksonville Fire and Rescue Department". Fire Departments. Retrieved 21 June 2014.