Jefferson, New York | |
|---|---|
 | |
 Location in Schoharie County and the state of New York. | |
| Coordinates: 42°29′55″N 74°36′6″W / 42.49861°N 74.60167°W | |
| Country | United States |
| State | New York |
| County | Schoharie |
| Area | |
| • Total | 43.41 sq mi (112.44 km2) |
| • Land | 43.25 sq mi (112.02 km2) |
| • Water | 0.16 sq mi (0.42 km2) |
| Elevation | 1,991 ft (607 m) |
| Population (2020) | |
| • Total | 1,333 |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 12093 |
| Area code | 607 |
| FIPS code | 36-38440 |
| GNIS feature ID | 0979106 |
| Website | Town website |
Jefferson is a town in Schoharie County, New York, United States. The population was 1,333 at the 2020 census.[3] The town is on the southwestern border of the county and is east of Oneonta.
- ^ "2016 U.S. Gazetteer Files". United States Census Bureau. Retrieved July 5, 2017.
- ^ Cite error: The named reference
USCensusEst2016was invoked but never defined (see the help page). - ^ United States Census Bureau, 2020 U.S. Census Results, Fulton town, Schoharie County, New York https://www.census.gov/search-results.html?searchType=web&cssp=SERP&q=Jefferson%20town,%20Schoharie%20County,%20New%20York