Jefferson, South Dakota | |
|---|---|
 Location in Union County and the state of South Dakota | |
| Coordinates: 42°36′15″N 96°33′58″W / 42.60417°N 96.56611°W | |
| Country | United States |
| State | South Dakota |
| County | Union |
| Incorporated | 1895[1] |
| Area | |
| • Total | 0.51 sq mi (1.32 km2) |
| • Land | 0.51 sq mi (1.32 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 1,116 ft (340 m) |
| Population | |
| • Total | 475 |
| • Density | 931.37/sq mi (359.27/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 57038 |
| Area code | 605 |
| FIPS code | 46-32700 |
| GNIS feature ID | 1267441[3] |
Jefferson is a city in Union County, South Dakota, United States. The population was 475 at the 2020 census.[5] It is part of the Sioux City, IA-NE-SD Metropolitan Statistical Area. Jefferson was founded in 1859. Every year the citizens of Jefferson and surrounding area celebrate the founding of Jefferson during "Jefferson Days", a festival that includes a movie in the park, a car show, fireworks and parade.[6]
The city has the name of President Thomas Jefferson.[7]
- ^ "SD Towns" (PDF). South Dakota State Historical Society. Archived from the original (PDF) on February 10, 2010. Retrieved February 13, 2010.
- ^ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved October 15, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Jefferson, South Dakota
- ^ Cite error: The named reference
USCensusDecennial2020CenPopScriptOnlywas invoked but never defined (see the help page). - ^ "U.S. Census Bureau: Jefferson city, South Dakota". www.census.gov. United States Census Bureau. Retrieved May 6, 2022.
- ^ "Archived copy" (PDF). Archived from the original (PDF) on March 16, 2012. Retrieved January 9, 2011.
{{cite web}}: CS1 maint: archived copy as title (link) - ^ Federal Writers' Project (1940). South Dakota place-names, v.1-3. American guide series. University of South Dakota. p. 43.