Jefferson Township, Brown County, Ohio

Jefferson Township, Brown County, Ohio
Township
Farmstead southeast of Russellville
Farmstead southeast of Russellville
Location of Jefferson Township in Brown County
Location of Jefferson Township in Brown County
Coordinates: 38°51′21″N 83°47′28″W / 38.85583°N 83.79111°W / 38.85583; -83.79111
CountryUnited States
StateOhio
CountyBrown
Area
 • Total
23.47 sq mi (60.78 km2)
 • Land23.45 sq mi (60.74 km2)
 • Water0.01 sq mi (0.03 km2)
Elevation
[1]
925 ft (282 m)
Population
 (2020)
 • Total
1,407
 • Density60/sq mi (23/km2)
Time zoneUTC-5 (Eastern (EST))
 • Summer (DST)UTC-4 (EDT)
FIPS code39-38528[2]
GNIS feature ID1085799[1]

Jefferson Township is one of the sixteen townships of Brown County, Ohio, United States. The 2020 census found 1,407 people in the township.[3]

  1. ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  3. ^ "Jefferson township, Brown County, Ohio - Census Bureau Profile". United States Census Bureau. Retrieved May 26, 2023.