Lake Alfred, Florida | |
|---|---|
| City of Lake Alfred | |
 Location in Polk County and the state of Florida | |
| Coordinates: 28°06′15″N 81°43′35″W / 28.10417°N 81.72639°W | |
| Country | United States of America |
| State | Florida |
| County | Polk |
| Incorporated | 1915[1] |
| Government | |
| • Mayor | Nancy Z. Daley |
| • Vice Mayor | Mac Fuller |
| • Commissioners | Jack Dearmin, Brent Eden, and Charles Lake |
| • City Manager | Ryan Leavengood |
| • City Clerk | Linda Bourgeois |
| Area | |
| • Total | 13.10 sq mi (33.93 km2) |
| • Land | 9.20 sq mi (23.82 km2) |
| • Water | 3.90 sq mi (10.10 km2) |
| Elevation | 131 ft (40 m) |
| Population (2020) | |
| • Total | 6,374 |
| • Density | 692.90/sq mi (267.54/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 33850 |
| Area code | 863 |
| FIPS code | 12-37525[4] |
| GNIS feature ID | 2404856[3] |
| Website | mylakealfred |
Lake Alfred is a city in Polk County, Florida, United States. It is part of the Lakeland–Winter Haven Metropolitan Statistical Area. The population was approximately 6,374 at the 2020 US census.
- ^ "Guide to Polk, Auburndale". The Ledger. Archived from the original on March 6, 2012. Retrieved September 25, 2010.
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved October 31, 2021.
- ^ a b U.S. Geological Survey Geographic Names Information System: Lake Alfred, Florida
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.