Lake San Cristobal | |
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Location | Hinsdale County, Colorado |
Coordinates | 37°58′15″N 107°17′27″W / 37.97083°N 107.29083°W |
Lake type | Barrier lake |
Basin countries | United States |
Max. length | 3.3 km (2.1 mi) |
Surface area | 1.34 km2 (0.52 sq mi) |
Max. depth | 27 m (89 ft) |
Water volume | 14,000,000 m3 (490,000,000 cu ft) |
Surface elevation | 2,744 m (9,003 ft) |
References | [1][2] |
Lake San Cristobal is a lake in the U.S. state of Colorado. Located in the San Juan Mountains at an elevation of 9,003 feet (2,744 m), the freshwater lake is 2.1 miles (3.4 km) long, up to 89 feet (27 m) deep, has a surface area of 0.52 square miles (1.3 km2), and holds about 11,000 acre-feet (14,000,000 m3) of water.[2] The town of Lake City, a few miles to the north, is named after Lake San Cristobal.[3] The name San Cristóbal means Saint Christopher in the Spanish language. Many old silver mines are near the lake and it is very clean and well kept, and stocked with Rainbow Trout.