Lanesville, Indiana | |
|---|---|
 | |
 Location of Lanesville in Harrison County, Indiana. | |
| Coordinates: 38°14′19″N 85°59′8″W / 38.23861°N 85.98556°W | |
| Country | United States |
| State | Indiana |
| County | Harrison |
| Township | Franklin |
| Area | |
• Total | 0.94 sq mi (2.44 km2) |
| • Land | 0.94 sq mi (2.44 km2) |
| • Water | 0.00 sq mi (0.00 km2) |
| Elevation | 702 ft (214 m) |
| Population (2020) | |
• Total | 935 |
| • Density | 993.62/sq mi (383.77/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 47136 |
| Area code | 812 |
| FIPS code | 18-42048[3] |
| GNIS feature ID | 0437616[2] |
Lanesville is a town in Franklin Township, Harrison County, Indiana, United States. The population was 935 at the 2010 census.
- ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
- ^ a b U.S. Geological Survey Geographic Names Information System: Lanesville, Indiana
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.