Milford, Wisconsin | |
|---|---|
 Town hall | |
 Location of Milford, Wisconsin | |
| Coordinates: 43°8′55″N 88°50′8″W / 43.14861°N 88.83556°W | |
| Country |  United States |
| State |  Wisconsin |
| County | Jefferson |
| Area | |
• Total | 35.1 sq mi (91.0 km2) |
| • Land | 34.0 sq mi (88.0 km2) |
| • Water | 1.2 sq mi (3.0 km2) |
| Elevation | 827 ft (252 m) |
| Population (2010) | |
• Total | 1,099 |
| • Density | 31/sq mi (12/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 55-51850[2] |
| GNIS feature ID | 1583714[1] |
Milford is a town in Jefferson County, Wisconsin, United States. The population was 1,099 at the 2010 census.[3] The unincorporated communities of Grellton, Hoopers Mill, Hubbleton, and Milford are located in the town.
- ^ a b U.S. Geological Survey Geographic Names Information System: Milford, Wisconsin
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Milford town, Jefferson County, Wisconsin". United States Census Bureau. Retrieved October 9, 2012.