Oxbow, North Dakota

Oxbow, North Dakota
Location of Oxbow, North Dakota
Location of Oxbow, North Dakota
Coordinates: 46°39′46″N 96°48′39″W / 46.66278°N 96.81083°W / 46.66278; -96.81083
CountryUnited States
StateNorth Dakota
CountyCass
FoundedOctober 25, 1988
Government
 • MayorJim Nyhof
Area
 • Total
1.53 sq mi (3.97 km2)
 • Land1.53 sq mi (3.97 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation915 ft (279 m)
Population
 • Total
381
 • Estimate 
(2023)[4]
371
 • Density248.69/sq mi (96.00/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
58047
Area code701
FIPS code38-60480
GNIS feature ID1033709[2]
Websiteoxbownd.com

Oxbow is a city in Cass County, North Dakota, United States. The population was 381 at the 2020 census.[3] It is an upscale bedroom community located 15 miles (24 km) south of Fargo. It was incorporated as a city October 25, 1988.

  1. ^ "ArcGIS REST Services Directory". United States Census Bureau. Retrieved September 20, 2022.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Oxbow, North Dakota
  3. ^ a b "Explore Census Data". United States Census Bureau. Retrieved October 13, 2023.
  4. ^ Cite error: The named reference USCensusEst2022 was invoked but never defined (see the help page).