Rudd Township | |
|---|---|
 Location in Floyd County | |
| Coordinates: 43°09′45″N 92°51′36″W / 43.16250°N 92.86000°W | |
| Country |  United States |
| State |  Iowa |
| County | Floyd |
| Area | |
| • Total | 35.24 sq mi (91.28 km2) |
| • Land | 35.24 sq mi (91.28 km2) |
| • Water | 0 sq mi (0 km2) 0% |
| Elevation | 1,148 ft (350 m) |
| Population (2000) | |
| • Total | 693 |
| • Density | 19.7/sq mi (7.6/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP codes | 50435, 50461, 50471 |
| GNIS feature ID | 0468646 |
Rudd Township is one of twelve townships in Floyd County, Iowa, USA. As of the 2000 census, its population was 693.[1]
- ^ "U.S. Census website". Retrieved May 15, 2009.