Seymour, Iowa

Seymour, Iowa
City
A city park in the central square of Seymour, Iowa
A city park in the central square of Seymour, Iowa
Location of Seymour, Iowa
Location of Seymour, Iowa
Coordinates: 40°40′56″N 93°07′16″W / 40.68222°N 93.12111°W / 40.68222; -93.12111
CountryUSA
State Iowa
CountyWayne
Area
 • Total2.39 sq mi (6.20 km2)
 • Land2.39 sq mi (6.20 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation1,076 ft (328 m)
Population
 (2020)
 • Total634
 • Density265.05/sq mi (102.32/km2)
Time zoneUTC−6 (Central (CST))
 • Summer (DST)UTC−5 (CDT)
ZIP code
52590
Area code641
FIPS code19-71760
GNIS feature ID2395851[2]

Seymour is a city in Wayne County, Iowa, United States. The population was 634 at the time of the 2020 census.[3]

  1. ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. ^ a b U.S. Geological Survey Geographic Names Information System: Seymour, Iowa
  3. ^ "2020 Census State Redistricting Data". census.gov. United states Census Bureau. Retrieved August 12, 2021.