Shueyville, Iowa

Shueyville, Iowa
Location of Shueyville, Iowa
Location of Shueyville, Iowa
Coordinates: 41°50′53″N 91°38′55″W / 41.84806°N 91.64861°W / 41.84806; -91.64861
Country United States
State Iowa
CountyJohnson
Area
 • Total1.86 sq mi (4.83 km2)
 • Land1.86 sq mi (4.83 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
801 ft (244 m)
Population
 (2020)
 • Total731
 • Density392.17/sq mi (151.45/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
FIPS code19-72840
GNIS feature ID0461591

Shueyville is a city in Johnson County, Iowa, United States. It is part of the Iowa City, Iowa Metropolitan Statistical Area. The population was 731 at the time of the 2020 census.[2]

  1. ^ "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. ^ "2020 Census State Redistricting Data". census.gov. United states Census Bureau. Retrieved August 12, 2021.