  Skoba Island Location of Skoba Island  Skoba Island Skoba Island (Antarctic Peninsula) | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 65°03′33″S 64°12′37″W / 65.05917°S 64.21028°W |
| Archipelago | Wilhelm Archipelago |
| Area | 2.8 ha (6.9 acres) |
| Length | 416 m (1365 ft) |
| Width | 176 m (577 ft) |
| Administration | |
| Administered under the Antarctic Treaty System | |
| Demographics | |
| Population | uninhabited |
Skoba Island (Bulgarian: остров Скоба, romanized: ostrov Skoba, IPA: [ˈɔstrof ˈskɔbɐ]) comprises four abutting rocky islets 416 m long in south–north direction and 176 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 2.8 ha.[1]
The feature is so named because of its shape supposedly resembling a bracket symbol ('skoba' in Bulgarian), and in association with other descriptive names of islands in the area.[1]
- ^ a b Skoba Island. SCAR Composite Gazetteer of Antarctica