Native name: Остров св. Иван | |
---|---|
Geography | |
Location | Black Sea |
Coordinates | 42°26′19″N 27°41′34″E / 42.43861°N 27.69278°E |
Area | 0.66 km2 (0.25 sq mi) |
Length | 0.880 km (0.5468 mi) |
Width | 0.510 km (0.3169 mi) |
Highest elevation | 33 m (108 ft) |
Administration | |
Demographics | |
Population | 5 humans |
St. Ivan Island (Bulgarian: остров св. Иван, ostrov Sveti Ivan) is the largest Bulgarian island in the Black Sea, with an area of 0.66 square kilometres (0.25 square miles).[1] It lies off the Bulgarian Black Sea Coast near Sozopol, a town with rich history and a popular tourist place, and is separated by a strait several hundred metres long from the small neighbouring St. Peter Island. Standing at 33 metres (108 feet) above sea level, it is also the highest of the Bulgarian sea islands. It lies 920 metres (0.57 miles) from the Stolets peninsula, the location of Sozopol's Old Town.